n^2-20n+22=3

Solution for n^2-20n+22=3 equation:

Simplifying
n2 + -20n + 22 = 3

Reorder the terms:
22 + -20n + n2 = 3

Solving
22 + -20n + n2 = 3

Solving for variable 'n'.

Reorder the terms:
22 + -3 + -20n + n2 = 3 + -3

Combine like terms: 22 + -3 = 19
19 + -20n + n2 = 3 + -3

Combine like terms: 3 + -3 = 0
19 + -20n + n2 = 0

Factor a trinomial.
(1 + -1n)(19 + -1n) = 0

Subproblem 1
Set the factor '(1 + -1n)' equal to zero and attempt to solve:

Simplifying
1 + -1n = 0

Solving
1 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1n = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1n = 0 + -1
-1n = 0 + -1

Combine like terms: 0 + -1 = -1
-1n = -1

Divide each side by '-1'.
n = 1

Simplifying
n = 1
Subproblem 2
Set the factor '(19 + -1n)' equal to zero and attempt to solve:

Simplifying
19 + -1n = 0

Solving
19 + -1n = 0

Move all terms containing n to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + -1n = 0 + -19

Combine like terms: 19 + -19 = 0
0 + -1n = 0 + -19
-1n = 0 + -19

Combine like terms: 0 + -19 = -19
-1n = -19

Divide each side by '-1'.
n = 19

Simplifying
n = 19
Solution
n = {1, 19}